A cuboidal tank measuring 5m × 2.1 m × 4.… | Answer

Subject

Quantitative Aptitude

Topic

Mensuration

A cuboidal tank measuring 5m × 2.1 m × 4.5m is dug in one corner of a field measuring 13.5 m × 2.5m. The earth dug out is spread evenly over the remaining portion of the field. How much is the level of the field raised?
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ক)

4.03 m

খ)

3.17 m

গ)

2.03 m

ঘ)

2.9 m

ঙ)

None of these

Explanation

We know that, volume of cuboid = length × breadth × height ∴ Volume of earth dug out from the tank = 5m × 2.1 m × 4.5m = 47.25 m 3 Also, Volume of the cuboidal tank = volume of earth dug out from the tank. Now, the exposed area of the field upon which the earth dug out is spread evenly = area of the total field – area of the top face of the tank Area of the total field = 13.5 m × 2.5m = 33.75 sq. m. Area of the top face of the tank = 5m × 2.1 m = 10.5 sq. m. The exposed area of the field = (33.75 – 10.5) sq. ft. = 23.25 sq. m. Now, the earth dug out is spread evenly over 23.25 sq. m. area. If level of field raises by L m. then from volume constancy we can say, 23.25 × L = 47.25 ⇒ L ≈ 2.03 m

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A cuboidal tank measuring 5m × 2.1 m × 4.5m is dug in one corner of a field measuring 13.5 m × 2.5m. The earth dug out is spread evenly over the remaining portion of the field. How much is the level of the field raised?Reading

A cuboidal tank measuring 5m × 2.1 m × 4.5m is dug in one corner of a field measuring 13.5 m × 2.5m. The earth dug out is spread evenly over the remaining portion of the field. How much is the level of the field raised?

Explanation

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A cuboidal tank measuring 5m × 2.1 m × 4.5m is dug in one corner of a field measuring 13.5 m × 2.5m. The earth dug out is spread evenly over the remaining portion of the field. How much is the level of the field raised?
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