Subject

    Quantitative Aptitude

    Topic

    Miscellaneous

    A container contains a mixture of two liquids ‘P’ and ‘Q’ in the ratio of 7 : 5. When 9 litres of mixture is drawn off and then the container is filled with the same amount of 'Q', then the ratio of ‘P’ and ‘Q’ becomes 7:9. How many litres of liquid ‘P’ was contained by the container initially?

    ক)
    27 litres
    খ)
    21 litres
    গ)
    31 litres
    ঘ)
    42 litres
    ঙ)
    None of these

    Explanation

    Suppose the container initially contains 7x and 5x litres of ‘P’ and ‘Q’ respectively. Then, According to the question, Quantity of ‘P’ in the mixture left =(7x−712×9)=(7x−214) litres= \left( {7x - \frac{7}{{12}} \times 9} \right) = \left( {7x - \frac{{21}}{4}} \right)\ litres Quantity of ‘Q’ in the mixture left: =(5x+9−512×9)litres=(5x+214) litres= \left( {5x + 9 - \frac{5}{{12}} \times 9} \right) litres = \left( {5 x + \frac{{21}}{4}} \right)\ litres According to the question: ⇒(7x−214)5x+214=79⇒28x−2120x+21=79\begin{array}{l} \Rightarrow \frac{{\left( {7x - \frac{{21}}{4}} \right)}}{{5x + \frac{{21}}{4}}} = \frac{7}{9}\\ \Rightarrow \frac{{28x - 21}}{{20x + 21}} = \frac{7}{9} \end{array} ⇒ 252x – 189 = 140x + 147 ⇒ 112x = 336 ⇒ x = 3 ∴  Litres of liquid ‘P’ that was contained by the container initially = 7 × 3 = 21 Hence, the required answer is 21 litres

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