Subject
Quantitative Aptitude
Topic
Time and Work
A cistern is provided with two pipes A and B. A can fill a cistern in 20 minutes and B can empty it in 24 minutes. If A and B pipes are opened on alternate minutes, find in how many minutes, the cistern shall be full?
A cistern is provided with two pipes A and B. A can fill a cistern in 20 minutes and B can empty it in 24 minutes. If A and B pipes are opened on alternate minutes, find in how many minutes, the cistern shall be full?
ক)
4 hours 49 min.খ)
3 hours 49 min.গ)
3 hours 18 min.ঘ)
None of theseঙ)
Can’t be determinedExplanation
According to the given information, A can fill the cistern in 20 minutes ⇒ in one min the part of cistern filled by A = 1/20 Similarly, B can empty the cistern in 24 minutes ⇒ in one min the part of cistern emptied by B = 1/24 Now, the Part of the cistern filled in a span of 2 minutes ∴ Part of the cistern filled in (114 × 2) = 228 minutes Part of cistern remaining to be filled = 1 – (19/20) = 1/20 After 228 minutes, it’s pipe A’s turn to fill the cistern and it has to fill 1/20th part of the cistern. As stated earlier, pipe A will take 1 minute to fill the remaining part. ∴ total time = 228 + 1 = 229 minutes = 3 hours 49 minutesRelated questions
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