Subject
Quantitative Aptitude
Topic
Mensuration
A circular ring has an inner radius of 10 cm and outer radius of 20 cm. A point P is taken on its inner boundary and a point Q is taken on its outer boundary such that P, Q and centre of ring are collinear. Another point R is taken on the outer boundary such that PR = 2PQ. With PR as radius, a sphere is formed. What will be the volume of the sphere (in cubic cm)?
A circular ring has an inner radius of 10 cm and outer radius of 20 cm. A point P is taken on its inner boundary and a point Q is taken on its outer boundary such that P, Q and centre of ring are collinear. Another point R is taken on the outer boundary such that PR = 2PQ. With PR as radius, a sphere is formed. What will be the volume of the sphere (in cubic cm)?
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28564.54খ)
30645.67গ)
33493.33ঘ)
38734.77ঙ)
40342.14Explanation
Let centre of ring be N. A point P is taken on its inner boundary and a point Q is taken on its outer boundary such that P, Q and centre of ring are collinear. ⇒ PQ = QN – PN = 20 cm – 10 cm = 10 cm ⇒ PR = 2PQ = 20 cm Volume of sphere = (4/3) × 3.14 × 20 × 20 × 20 = 33493.33 cubic cmRelated questions
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