Subject

    Quantitative Aptitude

    Topic

    Probability

    A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb

    ক)
    5/12
    খ)
    7/12
    গ)
    3/14
    ঘ)
    1/12

    Explanation

    Total number of elementary events = 10C510C_5 Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is 3C1×7C43C_1\times7C_4 So,required probability = 3C1×7C410C5\frac{3C_1\times7C_4}{10C_5} = 5/12.

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