Subject

    Quantitative Aptitude

    Topic

    Probability

    A bag contains 7 green and 5 black balls. Three balls are drawn one after the other. The probability of all three balls being green, if the balls drawn are not replaced will be:

    ক)
    123/897
    খ)
    23/67
    গ)
    7/44
    ঘ)
    12/45

    Explanation

    Here, n(E) = 7C1×5C1×5C17C_1\times5C_1\times5C_1 And,  n(S) = 12C1×11C1×10C112C_1\times11C_1\times10C_1 P(S) =  7×6×512×11×10\frac{7\times6\times5}{12\times11\times10} = 7/44

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