Subject
Quantitative Aptitude
Topic
Probability
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
ক)
10/21খ)
11/21গ)
1/2ঘ)
2/7Explanation
Total number of balls = (2 + 3 + 2) = 7. Let S be the sample space. Then, n(S) = Number of ways of drawing 2 balls out of 7 = = 21 Let E = Event of drawing 2 balls, none of which is blue. n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls = = 10 Therefore, P(E) = n(E)/n(S) = 10/ 21.Related questions
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