Subject

    Quantitative Aptitude

    Topic

    Probability

    A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

    ক)
    10/21
    খ)
    11/21
    গ)
    2/7
    ঘ)
    5/7

    Explanation

    Total number of balls = (2 + 3 + 2) = 7. Let S be the sample space. Then, n(S) = Number of ways of drawing 2 balls out of 7 = 7C2 =(7 x 6)/ (2 x 1) = 21. Let E = Event of drawing 2 balls, none of which is blue. So, n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls. = 5C2 =(5 x 4)/ (2 x 1) = 10. So, P(E) = n(E)/ n(S) = 10/21.

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