Subject

    Quantitative Aptitude

    Topic

    Time and Work

    7 men and 3 boys finish a job in 10 days, while 3 men and 7 boys finish it in 15 days. 10 boys working together will finish it in

    ক)
    40 days
    খ)
    16 days
    গ)
    42 days
    ঘ)
    25 days
    ঙ)
    24 days

    Explanation

    Let’s assume that one man can do the entire work alone in m days And one boy can alone do the entire work alone in b days ∴part of work done by one man in one day = 1/m and part of work done by one boy in one day = 1/b Now, as per the given information: Work was finished by 7 men and 3 boys in 10 days. ∴work done by 7 men and 3 boys in one day = 1/10 ⇒7×1m+3×1b=110\Rightarrow 7 \times \frac{1}{m} + 3 \times \frac{1}{b} = \frac{1}{{10}}          ------(i) Also, Work was finished by 3 men and 7 boys in 15 days. ∴work done by 3 men and 7 boys in one day = 1/15 ⇒3×1m+7×1b=115 \Rightarrow 3 \times \frac{1}{m} + 7 \times \frac{1}{b} = \frac{1}{{15}}          ------(ii) Solving equations (i) and (ii) simultaneously, we get: (1/b) = (1/240) ∴part of work done by one boy in one day = 1/240 ∵ since 10 boys are working together, Part of work done by 10 boys in one day = 10/240 = 1/24 ∴it will take 24 days for 10 boys to finish the entire work.
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