Subject
Quantitative Aptitude
Topic
Number
(3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ?
(3x + 2) (2x - 5) = ax² + kx + n. What is the value of a - n + k ?
ক)
4খ)
1গ)
5ঘ)
3Explanation
(3x + 2) (2x - 5) = ..............(1) But (3x + 2)(2x - 5) = .......(2) so by comparing (1) & (2), we get a= 6, k= -11 , n= -10 (a - n + k) = 6 + 10 - 11 = 5.Related questions
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