Subject

    Quantitative Aptitude

    Topic

    Probability

    14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together.

    ক)
    11/379
    খ)
    21/628
    গ)
    24/625
    ঘ)
    26/247

    Explanation

    Total no of ways = (14 – 1)! = 13! Number of favorable ways = (12 – 1)! = 11! So, required probability = ((11!×3!)13!)\left(\frac{\left(\mathbf{11}\boldsymbol!\boldsymbol\times\mathbf3\boldsymbol!\right)}{\mathbf{13}\boldsymbol!}\right) = 39916800×66227020800\frac{39916800\times6}{6227020800} = 24625\frac{\mathbf{24}}{\mathbf{625}}

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