Subject

    Quantitative Aptitude

    Topic

    Partnership

    125 gallons of a mixture contains 20% water. What amount of additional water should be added such that the water content is raised to 25%

    ক)
    15/2 gallons
    খ)
    17/2 gallons
    গ)
    19/2 gallons
    ঘ)
    81/­3 gallons

    Explanation

    Let, x gallons water should be added. Here, 125 gallons of a mixture contains 20% water is (125× 20/100)= 25 gallons According to the question, 25+x = (125+x)×25/100 => 25+x = (125+x)×1/4 => 4(25+x) = 125+x => 100+4x = 125+x => 4x-x=125-100 => 3x=24 => x=24/3 So, x=81/3 So, 81/3 gallons water should be added. (Ans.)

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